Question 724790: If two cards are drawn without replacement from an ordinary deck, find the probabilities of the following results.
Q. The second is a heart, given that the first is a heart.
This question asks me to solve for
P(Second is a heart given that the first is a heart)= P(E and F)/ P(F)
I tried solving the first part "The second is a heart"
by doing this way. Let E: second is a heart
P(E) = 13/52.
At this stage, i'm completely lost how to get the second part " given that the first is a heart"
In this case, what should i do?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If two cards are drawn without replacement from an ordinary deck, find the probabilities of the following results.
Q. The second is a heart, given that the first is a heart.
This question asks me to solve for
P(Second is a heart given that the first is a heart)= P(E and F)/ P(F)
I tried solving the first part "The second is a heart"
by doing this way. Let E: second is a heart
P(E) = 13/52.
At this stage, i'm completely lost how to get the second part " given that the first is a heart"
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P(heart AND heart) = 13C2/52C2 = 1/17
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P(heart|heart) = (1/17)/(13/52) = (1/17)(52/13) = 0.2353
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Cheers,
Stan H.
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