SOLUTION: solve the equation on the interval 0 < or equal to theta < 2pi. tan^2 theta = 3/2 sec theta

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Question 724719: solve the equation on the interval 0 < or equal to theta < 2pi.
tan^2 theta = 3/2 sec theta
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve the equation on the interval 0 < or equal to theta < 2pi.
tan^2 theta = 3/2 sec theta
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tan(π/3)^2=(√3)^2=3
3/2 sec(π/3)=3/2cos(π/3)=3/2*1/2=3
solution: theta=π/3, 2π/3 (in quadrants I and II where cos and tan have the same sign)