SOLUTION: solve the equation on the interval 0 < or equal to theta < 2pi . 4cos^2 theta = 1

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Question 724718: solve the equation on the interval 0 < or equal to theta < 2pi .
4cos^2 theta = 1
Answer by solver91311(24713) About Me  (Show Source):
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Divide both sides by 4, take the square root. Then find all of the angles in the given interval where the cosine is equal to

John

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