SOLUTION: solve the equation on the interval 0 < or equal to theta < 2 pi . cot 2theta/3 = -root 3

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Question 724717: solve the equation on the interval 0 < or equal to theta < 2 pi . cot 2theta/3 = -root 3
Answer by lwsshak3(11628) About Me  (Show Source):
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solve the equation on the interval 0 < or equal to theta < 2 pi . cot 2theta/3 = -root 3
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cot2x/3=-√3
cot2x=-3√3=-√3/9
tan2x=-1/(3√3)=-√3/9
using inverse tan key of calculator set to radians:
2x≈π-0.1925, 2π-0.1925=2.9491,6.0907 in quadrants II and IV where tan<0
x≈1.4746, 3.0454