SOLUTION: Solve the following trigonometric equation for 0deg ≤ x ≤ 360deg sin x - 2sin2 x = 0

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Question 724565: Solve the following trigonometric equation for 0deg ≤ x ≤ 360deg
sin x - 2sin2 x = 0
Answer by lwsshak3(11628) About Me  (Show Source):
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Solve the following trigonometric equation for 0deg ≤ x ≤ 360deg
sin x - 2sin2 x = 0
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sinx-2sin^2x=0
sinx(1-2sinx)=0
sinx=0
x=0, 180º
..
1-2sinx=0
2sinx=1
sinx=1/2
x=30º, 150º