SOLUTION: How do i find the focus of the problem (y+3)^2=x-2

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Question 724278: How do i find the focus of the problem (y+3)^2=x-2
Answer by lwsshak3(11628) About Me  (Show Source):
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How do i find the focus of the problem (y+3)^2=x-2
This is an equation of a parabola that opens rightward.
Its basic form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
For given equation:
vertex: (2,-3)
axis of symmetry: y=3
4p=1
p=1/4
focus: (9/4,-3) (p-distance to the right of the vertex on the axis of symmetry)