SOLUTION: the sum of twice a first number and five times a second number is 99? if the second number is subtracted from five the first number the result is 45. Find the numbers.
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Question 724260: the sum of twice a first number and five times a second number is 99? if the second number is subtracted from five the first number the result is 45. Find the numbers. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! let the two number be a & b
:
Write an equation for each statement
:
"the sum of twice a first number and five times a second number is 99?"
2a + 5b = 99
:
"if the second number is subtracted from five the first number the result is 45.
Perhaps you mean:
"if the second number is subtracted from five times the first number the result is 45."
5a - b = 45
or
b = 5a - 45
:
In the 1st equation, replace b with (5a-45)
2a + 5(5a-45) = 99
2a + 25a - 225 = 99
27a = 99 + 225
27a = 324
a = 324/27
a = 12
:
Find b using b = 5a - 45
b = 5(12) - 45
b = 60 - 45
b = 15
:
Find the numbers. 12 & 15
;
;
Check this in the statement:
"the sum of twice a first number and five times a second number is 99?"
2(12) + 5(15) =
24 + 75 = 99
