SOLUTION: The two equal sides of an isosceles triangle are each 49 centimeters. If the base measures 40 centimeters, find the height h and the measure of the two equal angles θ. (Round

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Question 724090: The two equal sides of an isosceles triangle are each 49 centimeters. If the base measures 40 centimeters, find the height h and the measure of the two equal angles θ. (Round your answers to the nearest whole number.)
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The symmetry of an isosceles triangle ensures that half the measure of the base would be one leg of a right triangle and the measure of one of the two equal sides is the measure of the hypotenuse of this same right triangle. The height is then the other leg for this right triangle. If h=height, then:

h%5E2%2B%28%281%2F2%2940%29%5E2=49%5E2. That will help you get the height, h.

The measure of one of the two equal angles does not require the height. You just need half the base and the hypotenuse ( one of the equal sides).
cos%28a%29=%28%281%2F2%2940%29%2F%2849%29, where a is one of the equal angles of the isosceles triangle.