SOLUTION: the cinema sold 200 ticket for 22600 totally. if the denomination of the ticket were rs.100 and rs.120. how many ticket each denomination were sold.

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Question 724056: the cinema sold 200 ticket for 22600 totally. if the denomination of the ticket were rs.100 and rs.120. how many ticket each denomination were sold.
Found 3 solutions by mananth, josgarithmetic, josmiceli:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x= number of 100 rupee tickets
y= number of 120 rupee tickets

x + y = 200 .............1
Total value
100 x + 120 y = 22600 .............2
Eliminate y
multiply (1)by -120
Multiply (2) by 1
-120 x -120 y = -24000
100 x + 120 y = 22600
Add the two equations
-20 x = -1400
/ -20
x = 70
plug value of x in (1)
1 x + 1 y = 200
70 + y = 200
y = 200 -70
y = 130
y = 130
x= 70 number of 100 rupee tickets
y= 130 number of 120 rupee tickets
m.ananth@hotmail.ca

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
This might be understood if your "totally" means revenue is 22600 of the rs units were sold.

Let x = count of rs.100 tickets
Let y = count of rs.120 tickets
100x%2B120y=22600 and x%2By=200. Solve x and y in that system.

The first equation is simplifiable to 10x+12y=2260, or 5x+6y=1130, so a better system is:
5x%2B6y=1130
x%2By=200
Solve system for x and y.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = number of rs. 100 tickets sold
Let +b+ = number of rs. 120 tickets sold
given:
(1) +a+%2B+b+=+200+
(2) +100a+%2B+120b+=+22600+
--------------------------
(2) +10a+%2B+12b+=+2260+
(2) +5a+%2B+6b+=+1130+
Multiply both sides of (1) by +5+
and subtract (1) from (2)
(2) +5a+%2B+6b+=+1130+
(1) +-5a+-+5b+=+-1000+
+b+=+130+
and, since
(1) +a+%2B+b+=+200+
(1) +a+=+70+
70 rs. 100 tickets were sold
130 rs. 120 tickets were sold
check answer:
(2) +100a+%2B+120b+=+22600+
(2) +100%2A70+%2B+120%2A130+=+22600+
(2) +7000+%2B+15600+=+2260+
(2) +2260+=+2260+
OK