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Question 724026: Identify the vertex, focus, and directrix of the parabola. x=-1/4(y+1)^2+2 Thanks
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Identify the vertex, focus, and directrix of the parabola.
x=-1/4(y+1)^2+2
rewrite equation in basic form
x-2=-1/4(y+1)^2
(y+1)^2=-4(x-2)
Basic form of equation for a parabola that opens leftward: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex
For given equation:
vertex: (2-1)
axis of symmetry: y=-1
4p=4
p=1
focus: (1,-1) (p-distance to left of vertex on the axis of symmetry)
directrix: x=3 (p-distance to right of vertex on the axis of symmetry)
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