Question 7240: one side of a triangle is 2 inches more than the shortest side. the third side is twice the length of the shortest side. if the triangle perimeter is 37 inches, find the length of each
Answer by sabanasir(22)   (Show Source):
You can put this solution on YOUR website! well since the other two sides are conneccted with shortest then we say the shortest to be 'x'
now one side which is 2 inches more that of shortest side, it wud b:
x+2
and the 3rd side said to be twice shortest one's length then it wud b:
2x
now its said the perimeter. a perimeter is a sum of all the sidees' length, so:
meaning:
shortest side+second side+third sided = 37
(x)+(x+2)+(2x) = 37
x+ 2x + x = 37 -2
4x = 35( r u sure it is 37?? if it is then the lenthgs are to be in decimals)
x=35/4
x=8.75
now the side which was 2 inches more, its length is:
x+2=8.75 + 2=10.75
and the third and the last which was twice of 'x':
2x = 2(8.75)=17.5
sides are:
8.75,10.75,17.5
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