SOLUTION: 1. The length of a rectangle exceeds 3 times its width by 1 inch. If the length of the rectangle is diminished by 3 inches and the width is doubled, a new rectangle is formed whose
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Question 723682: 1. The length of a rectangle exceeds 3 times its width by 1 inch. If the length of the rectangle is diminished by 3 inches and the width is doubled, a new rectangle is formed whose perimeter is 46 inches. Find the dimensions of the original rectangle. (Please help, thanks! I don't understand what they meant by 'exceeds' what equation do I do? Please show work and steps!)
2. The length of a rectangle exceeds its width by 4 meters. If the width is doubled and the length is diminished by 2 meters, a new rectangle is formed whose perimeter is 8 meters more than the perimeter of the original rectangle. Find the dimensions of the original rectangle. (Again, please show work and steps. Thanks so much!) Answer by lynnlo(4176) (Show Source):
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