SOLUTION: If a rocket is launched with an initial velocity of 1600 feet per second, when will the rocket be 14,400 feet high? Use the formula h = vt - 16t^2 to solve the problem.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: If a rocket is launched with an initial velocity of 1600 feet per second, when will the rocket be 14,400 feet high? Use the formula h = vt - 16t^2 to solve the problem.      Log On


   



Question 723485: If a rocket is launched with an initial velocity of 1600 feet per second, when will the rocket be 14,400 feet high? Use the formula h = vt - 16t^2 to solve the problem.
Answer by Alan3354(69443) About Me  (Show Source):
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If a rocket is launched with an initial velocity of 1600 feet per second, when will the rocket be 14,400 feet high? Use the formula h = vt - 16t^2 to solve the problem.
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h = vt - 16t^2 = 14400
1600t - 16t^2 = 14400
solve for t.
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Why is that called a rocket? It's a projectile.
Rockets have thrust and accelerate after launch.