Question 72346This question is from textbook
: The number of long-dsitance phone calls between two cities in a certain time perio varies directly as the population p1 and p2 of the cities and inversely as the distane between them. If 10,000 calls are made between two cities 500 mi apart, having populations of 50,000 and 125,000, find the number of calls between two cities 800 mi apart, having populations of 20,000 and 80,000
This question is from textbook
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The number of long-dsitance phone calls between two cities in a certain time perio varies directly as the population p1 and p2 of the cities and inversely as the distane between them. If 10,000 calls are made between two cities 500 mi apart, having populations of 50,000 and 125,000, find the number of calls between two cities 800 mi apart, having populations of 20,000 and 80,000
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Formula: # of calls = k p1*p2/d where d is the distance from p1 to p2
10000 = k 50000*125000/500
k = 0.0008
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EQUATION:
number = (0.0008)P1*p2/d
number = 0.0008*20000*80000/800
number = 1600
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Cheers,
Stan H>
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