|  | 
| 
 
 
| Question 723416:  Suppose the value of a car depreciates linearly for 15 years after it is bought.  Also, suppose the value of the new car is $25,000 and the value 10 years after it is bought is $9,000.  Let y be the value of the car x years after it is bought. Find a linear equation relating x and y.  Write in y = mx + b form.  I came up with y=1,600 + 23,400.  I don't feel this is correct???
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website!  Suppose the value of a car depreciates linearly for 15 years after it is bought. Also, suppose the value of the new car is $25,000 and the value 10 years after it is bought is $9,000. Let y be the value of the car x years after it is bought. Find a linear equation relating x and y. Write in y = mx + b form. I came up with y=1,600 + 23,400. I don't feel this is correct??? ----
 You have 2 points relating time and value: (0,25000) and (10,9000)
 ----
 slope = (9000-25000)/(10-0) = 1600
 ------
 intercept is f(0) = 25000
 ------------
 Equation:
 value = 1600(years) + 25000
 v = 1600x + 25000
 =======================
 Cheers,
 Stan H.
 =======================
 | 
  
 | 
 |  |  |