SOLUTION: Solve the following 2 x 2 systems using substitutions y= 3x - 3 3x + 5y =57

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Question 72330: Solve the following 2 x 2 systems using substitutions
y= 3x - 3
3x + 5y =57
Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
y= 3x - 3
3x + 5y =57
Replace the y in the second equation with 3x-3;
3x + 5(3x-3)=57
distribute 5;
3x + 15x - 15 =57
add like terms and add 15 to both sides;
18x=57+15
18x = 72
x = 4
Now replace x with 4;
y=3(4)-3
y = 12-3
y=9
:)