Question 723008: (y^3-y^2-3y-9)/(y+1)
the ^ is suppose to mean its a exponent so y exponent 3 and y exponent 2
**Sorry about that Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! The exponents are understood.
y^3 is the usual way to type and is y^2 the usual way to type
What is not clear is what to do with that rational expression.
We can factor or divide. Maybe one of those two choices is what you wanted.
FACTORING:
and we see that it cannot be simplified.
The possible rational zeros of are -9, -3, -1, 1, 3, and 9.
It was easy to try -3, -1, 1, and 3.
Since 3 was a zero had to be a factor.
Dividing by we get and cannot be factored further because it has no zeros.
(There are no real solutions to ).
DIVIDING:
We get for a quotient and a remainder of .
