SOLUTION: Help please! Express y as a function of x in 2{{{ log (52, y) }}} = 1/3 {{{ log (52, x^2 +1) }}} - x^1/2 - C where C>0 constant.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Help please! Express y as a function of x in 2{{{ log (52, y) }}} = 1/3 {{{ log (52, x^2 +1) }}} - x^1/2 - C where C>0 constant.      Log On


   

Question 722999: Help please!
Express y as a function of x in 2+log+%2852%2C+y%29+ = 1/3 +log+%2852%2C+x%5E2+%2B1%29+ - x^1/2 - C where C>0 constant.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Express y as a function of x in 2+log+%2852%2C+y%29+ = 1/3 +log+%2852%2C+x%5E2+%2B1%29+ - x^1/2 - C where C>0 constant.
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2log52(y) = (1/3)log52(x^2+1) - sqrt(x) - C
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2log52(y)-(1/3)log52(x^2+1) = -sqrt(x)-C
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log62[y^2/(x^2+1)^(1/3)] = -sqrt(x)-C
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y^2/(x^2+1)^(1/3) = 52^(-sqrt(x)-C)
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y^2 = (x^2+1)^(1/3)*52^(-sqrt(x)-C)
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y = +-sqrt[(x^2+1)^(1/3)*52^(-sqrt(x)-C)
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Cheers,
Stan H.