SOLUTION: We just started solving polynomials by grouping. My teacher said this is a baby step for quadratic equations but I don't really get it.
The problem I need help with is: 2a^2+3a+6a
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-> SOLUTION: We just started solving polynomials by grouping. My teacher said this is a baby step for quadratic equations but I don't really get it.
The problem I need help with is: 2a^2+3a+6a
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Question 722872: We just started solving polynomials by grouping. My teacher said this is a baby step for quadratic equations but I don't really get it.
The problem I need help with is: 2a^2+3a+6a+a
We're supposed to group the first two and last two sets of numbers based on the greatest common factor.
I got this: a(2a+3)+a(6+1)
My teacher said the two groups of numbers in parentheses are supposed to match. Mine doesn't and I got confused. Please help! Found 2 solutions by Alan3354, 119078:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! We just started solving polynomials by grouping. My teacher said this is a baby step for quadratic equations but I don't really get it.
The problem I need help with is: 2a^2+3a+6a+a
We're supposed to group the first two and last two sets of numbers based on the greatest common factor.
I got this: a(2a+3)+a(6+1)
My teacher said the two groups of numbers in parentheses are supposed to match. Mine doesn't and I got confused.
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1st, polynomials are not solved. Equations are solved.
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I think you mean factoring by grouping.
2a^2+3a+6a+a
That has 3 a terms, I suspect a typo.
= 2a^2 + 10a
= 2a*(a + 5)
You can put this solution on YOUR website! Look at the common variables. Add those up together and you will have a problem that looks like 2a^2+10a. This should be easier to factor. There is no way your right to do the grouping on this problem. Teachers are tricky they will bring things back in your present homework that was from the past lesson to make sure you still remember. Now, if I'm wrong I owe you a donut and I would say ask your teacher before class or after to explain it either in a different way or again.
Spoiler here is how I did the whole problem:
2a^2+3a+6a+a
2a^2+10a
2a(a+5)
