SOLUTION: The two smaller angles of a parallelogram have equal measures, and the two larger angles each measure 27 degrees less than twice each smaller angle. Find the measure of each angle.

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Question 722722: The two smaller angles of a parallelogram have equal measures, and the two larger angles each measure 27 degrees less than twice each smaller angle. Find the measure of each angle.
Answer by 119078(26) About Me  (Show Source):
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Brake it down. The larger ones are first 2 as big so 2x, but then they are -27 after you do that so completely the larger ones are 2x-27. The total amount a parallelogram's angles should equal is 360. Like a square it has four corners, but one more than a triangle. A triangle has a total of 180 for all 3 of its sides so just times the number of corners by 60 and you will get the total angle degree. so 4%2A60=360
two smaller angles=x
two larger=2x-27
total angles=360
put this into a formula. You need to add all of the angles together in order to the total angle #.
360=2x-27%2B2x-27%2Bx%2Bx
Add like terms
360=6x-54
Add 54 to both sides
360%2B54=6x-54%2B54
414=6x
divide 6 on each side.
414%2F6=6x%2F6
69=x
Answers:
Larger=111
Smaller=69
Don't just look at a problem and think it is too hard at that one spot chances are you have done that problem before just it is saying it in a different order to mess with you. I hope you can think through the next one like this, if not come back to this one and remember the magic that is in that! Have fun!