SOLUTION: I don't understand the method needed to be used to find the area of a rectangle if: perimeter=64 units length= x units width= 2x-11 units

Algebra ->  Rectangles -> SOLUTION: I don't understand the method needed to be used to find the area of a rectangle if: perimeter=64 units length= x units width= 2x-11 units      Log On


   



Question 722580: I don't understand the method needed to be used to find the area of a rectangle if:
perimeter=64 units
length= x units
width= 2x-11 units

Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Use fundamental relationships. length*width is area for a rectangle. Perimeter of a rectangle is 2 times the sum of length and width.

In symbols, or variables, if L is length and W is width, then:
2L+2W=perimeter, and L*W= area.

You are looking for area for your described rectangle. Use perimeter to find your unknown x, and then use this in your calculation for area, L*W.