consecutive even positive integers
Smaller integer = x
Larger integer = x+2
both of which is greater than 5
x > 5, and since it is an integer, x ≧ 6
their sum is less than 23
x + (x+2) < 23
x + x + 2 < 23
2x + 2 < 23
2x < 21
x < 10.5
x ≦ 10
x ≧ 6 is the same 6 ≦ x so we are to use
integers in this interval
6 ≦ x ≦ 10
x x+2
6 8
8 10
10 12
Edwin