SOLUTION: Venus usually jogs to school and walks home. Today her rate going was 2 miles per hour more than her rate returning. If it took her 20 minutes to go to school and 30 minutes to ret
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Venus usually jogs to school and walks home. Today her rate going was 2 miles per hour more than her rate returning. If it took her 20 minutes to go to school and 30 minutes to ret
Log On
Question 721427: Venus usually jogs to school and walks home. Today her rate going was 2 miles per hour more than her rate returning. If it took her 20 minutes to go to school and 30 minutes to return him by the same route, find her rate each way. Please help I'm having trouble getting the answer Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Venus usually jogs to school and walks home.
Today her rate going was 2 miles per hour more than her rate returning.
If it took her 20 minutes to go to school and 30 minutes to return him by the same route, find her rate each way.
:
Since we are using mph, change 20 min to 1/3 hr and 30 min to 1/2 hr
:
let x = her walking rate
then
(x+2) = her jogging rate
:
The dist each way is the same,
write distance equation, dist = speed * time
: *x = (x+2)
multiply both sides by 6, resulting in:
3x = 2(x+2)
3x = 2x + 4
3x - 2x = 4
x = 4 mph is her walking rate
then
6 mph is the jogging rate
:
:
Confirm this by finding the distances, should be the same each way 4 = 2 mi 6 = 2 mi
