SOLUTION: A rectangle has perimeter equal to 28, what is the maximum possible area of this rectangle.

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Question 721157:
A rectangle has perimeter equal to 28, what is the maximum possible area of this rectangle.
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
P=2L+2W
28=2X+2X
28=4X
4X=28
X=28/4
X=7 FOR THE SIDES OF A SQUARE.
AREA=LW
AREA=7*7
AREA=49 IS THE MAXIMUM AREA.
PROOF:
P=2L+2W
P=2(L+W)
28=2(L+W)
(L+W)=28/2
L+W=14
LET THE SIDES BE L=6.9 & W= 7.1
AREA=6.9*7.1
AREA=48.99