SOLUTION: (n)^2+(2n-1)^2=(2n+1)^2

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Question 721146: (n)^2+(2n-1)^2=(2n+1)^2
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
(n)^2+(2n-1)^2=(2n+1)^2
N^2+4N^2-4N+1=4N^2+4N+1
N^2-4N-4N=0
N^2-8N=0
N(N-8)=0
N=0 ANS
N-8=0
N=8 ANS.
PROOFS:
0^2+(2*0-1)^2=(2*0+1)^2
0+-1^2=1^2
1=1
8^2+(2*8-1)^2=(2*8+1)^2
64+(16-1)^2=(16+1)^2
64+15^2=17^2
64+225=289
289=289