SOLUTION: the sum of two numbers is 18. the total of 3 times the smaller and twice the larger is 44. find the 2 numbers

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Question 72112This question is from textbook
: the sum of two numbers is 18. the total of 3 times the smaller and twice the larger is 44. find the 2 numbers This question is from textbook

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let the two numbers be a and b where a is the smaller of the two. From the problem description, you can write the equations:
1) a%2Bb+=+18 The sum of the two numbers is 18.
2) 3a%2B2b+=+44 The total (sum) of three times the smaller and twice the larger is 44
Rewrite equation 1) as:
1a) a+=+18-b substitute into equation 2) and solve for b.
2a) 3%2818-b%29%2B2b+=+44 Simplify.
54-3b%2B2b+=+44
54-b+=+44 Subtract 54 from both sides.
-b+=+-10 Multiply both sides by -1
b+=+10
a+=+18-b
a+=+18-10
a+=+8
The two numbers are: 8 and 10