SOLUTION: A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16 kg mixture was worth $6.70/kg. How many kilograms of each type were used. Algebra must be u
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Question 721037: A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16 kg mixture was worth $6.70/kg. How many kilograms of each type were used. Algebra must be used. Thank You. Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! u = kgs of low priced $6/kg
v = kgs of high priced $8.80/kg
M = 16 kg of mixture
T = $6.70/kg of mixture
L = $6/kg
H = $8.80/kg
The unknown variables to solve for and values to find are u and v.
and
Solve symbolically for u and v, and then substitute given values to find values of u and v.
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