SOLUTION: The sum of Louise's age and Todd's age is 34 years. Five years ago, the sum of twice Louise's age and three times Todd's age was 61 years. How old are they now?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The sum of Louise's age and Todd's age is 34 years. Five years ago, the sum of twice Louise's age and three times Todd's age was 61 years. How old are they now?      Log On


   



Question 721033: The sum of Louise's age and Todd's age is 34 years. Five years ago, the sum of twice Louise's age and three times Todd's age was 61 years. How old are they now?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = Louise's age now
Let +b+ = Todd's age now
+a+-+5+ = Louise's age 5 yrs ago
+b+-+5+ = Todd's age 5 yrs ago
-------------
given:
(1) +a+%2B+b+=+34+
(2) +2%2A%28+a-5+%29+%2B+3%2A%28+b-5+%29+=+61+
-----------------------------
(2) +2a+-+10+%2B+3b+-+15+=+61+
(2) +2a+%2B+3b+=+61+%2B+25+
(2) +2a+%2B+3b+=+86+
-------------------
Multiply both sides of (1) by +2+
and subtract (1) from (2)
(2) +2a+%2B+3b+=+86+
(1) +-2a+-+2b+=+-68+
+b+=+18+
and, since
(1) +a+%2B+b+=+34+
(1) +a+=+34+-+18+
(1) +a+=+16+
Louise's age now is 16
Todd's age now is 18
----------
check:
(2) +2%2A%28+a-5+%29+%2B+3%2A%28+b-5+%29+=+61+
(2) +2%2A%28+16-5+%29+%2B+3%2A%28+18-5+%29+=+61+
(2) +22+%2B+39+=+61+
(2) +61+=+61+
OK