SOLUTION: How many liters of a 20%-alcohol solution must be mixed with 50 liters of a solution that is 60% alcohol to get a solution that is 30% alcohol?

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Question 720894: How many liters of a 20%-alcohol solution must be mixed with 50 liters of a solution that is 60% alcohol to get a solution that is 30% alcohol?
Answer by josgarithmetic(39617) About Me  (Show Source):
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Find the expression for the amount of pure alcohol in the new solution. Find the expression for the total quantity of new solution. The ratio of those will be the fraction of this new solution as the alcohol. The variable for the amount of 20% alcohol is in the numerator and in the denominator. Solve the rational equation for this variable.