SOLUTION: 2 planes took off from Milwaukee. First plane is traveling 3 times as fast as the second plane. After traveling the same direction for 2 hours they are 368 miles apart. Whats the a

Algebra ->  Test -> SOLUTION: 2 planes took off from Milwaukee. First plane is traveling 3 times as fast as the second plane. After traveling the same direction for 2 hours they are 368 miles apart. Whats the a      Log On


   



Question 720876: 2 planes took off from Milwaukee. First plane is traveling 3 times as fast as the second plane. After traveling the same direction for 2 hours they are 368 miles apart. Whats the average speed of each plane.
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Which Plane___________rate______________time________________distance
First Fast____________3r________________2___________________3r*2
Second Slower__________r________________2___________________r*2
Their Difference________________________2___________________368

One plane went farther than the other creating distance between them of 368 miles. The difference from "distance" column expressions is highlight%283r%2A2-r%2A2=368%29. Obviously showing the subtraction of the slower plane distance from the faster plane distance is most sensible. Solve for r. Compute 3r.

Note, equation simplifies to 4r=368.