SOLUTION: Solve the following system of equation 3 varibles x+2y+z=4;4y-3z=1 ;y+5z=6sove for. X y z. Thanks
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Question 720864
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Solve the following system of equation 3 varibles x+2y+z=4;4y-3z=1 ;y+5z=6sove for. X y z. Thanks
Answer by
checkley79(3341)
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x+2y+z=4
4y-3z=1
y+5z=6 MULTIPLY BY -4 & ADD TO THE PREVIOUS EQUATION.
-4Y-20Z=-24
4Y-3Z=1
--------------
-23Z=-23
Z=-23/-23
Z=1 ANS.
Y+5*1=6
Y+5=6
Y=6-5
Y=1 ANS.
X+2*1+1=4
X+2+1=4
X+3=4
X=4-3
X=1 ANS.