Question 720523: Find three consecutive even integers so that the first plus eight times the second is eight times the third. Answer by ramsinaaa(9) (Show Source):
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let integer 1 be x
let integer 2 be x+2
let integer 3 be x+4
the problem translated to an equation is: int1+8(int2)=8(int3)
so.....
(x)+8(x+2)=8(x+4)
x+8x+16=8x+32
9x+16=8x+32
x=16
integer 1= 16
integer 2= 18
integer 3= 20
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