Question 720378: find the exact value of the remaining trigonometric functions:
1. cotθ = 12/5, cosθ < 0
2. cosθ = -3/5, θ in quadrant III
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! find the exact value of the remaining trigonometric functions:
1. cotθ = 12/5, cosθ < 0
let O=opposite side
let A=adjacent side
H=hypotenuse
..
cot>0 and cos<0 only in quadrant III
cotθ = 12/5=A/O
A=-12, O=-5
H=√(O^2+A^2)=√(144+25)=√169=13
sinθ=-5/13
cosθ=-12/13
tanθ=5/12
cscθ=-13/5
secθ=-13/12
cotθ=12/5
..
2. cosθ = -3/5, θ in quadrant III
sin and cos<0
cosθ=-3/5=A/H
A=-3, H=5
O=√(H^2-A^2)=√(25-9)=√16=-4
sinθ=-4/5
cosθ=-3/5
tanθ=4/3
cscθ=-5/4
secθ=-5/3
cotθ=3/4
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