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There are three consecutive even integers such that 3 times the second is 6 more than the sum of the first and third. Find these integers
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There are three consecutive even integers such that 3 times the second is 6 more than the sum of the first and third. Find these integers
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Question 720325:
There are three consecutive even integers such that 3 times the second is 6 more than the sum of the first and third. Find these integers Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! LET X, X+2 & X+4 BE THE 3 EVEN INTEGERS.
3(X+2)=6+X+(X+4)
3X+6=6+2X+4
3X-2X=6+4-6
X=4 ANS. FOR THE SMALLER INTEGER.
4+2=6 ANS. FOR THE MIDDLE INTEGER.
4+4=8 ANS. FOR THE LARGER INTEGER.
PROOF:
3*6=6+4+8
18=18
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