SOLUTION: If the perimeter of a tennis court is 228 feet and the width is three feet shorter than half of the length, what are the dimensions of the tennis court?

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Question 720321:
If the perimeter of a tennis court is 228 feet and the width is three feet shorter than half of the length, what are the dimensions of the tennis court?

Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
P=2L+2W
W=L/2-3
228=2L+2(L/2-3)
228=2L+L-6
3L=228+6
3L=134
L=234/3
L=78 ANS. FOR THE LENGTH.
W=78/2-3=39-3=36 ANS. FOR THE WIDTH.
PROOF:
228=2*78+2*36
228=156+72
228=228