SOLUTION: If Person A can pain the house 6 times as fast as person B. The year A and B worked together it took them 9 days. How long would it take each to paint the house?
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Question 720244: If Person A can pain the house 6 times as fast as person B. The year A and B worked together it took them 9 days. How long would it take each to paint the house? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! If Person A can pain the house 6 times as fast as person B.
The year A and B worked together it took them 9 days.
How long would it take each to paint the house?
:
let a = time required by person A to paint the house alone
then it says, A is 6 time faster, or B take 6 times as long, therefore:
6a = time required by B alone
:
Let the completed job = 1
:
Each will do a fraction of the job, the two fractions add up to 1
: + = 1
mult by 6a to clear the denominators, resulting in:
6(9) + 9 = 6a
54 + 9 = 6a
63 = 6a
a = 63/6
a = 10.5 days for A alone
then
6(10.5) = 63 days B working alone
:
:
See if that works out + =
.857 + .143 = 1
