SOLUTION: A)Treveon paddled 27 miles downstream in his boat. The speed of the water current was 3 mph.
B)Brian paddled 15 miles across the lake in his boat. He was traveling on still wa
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-> SOLUTION: A)Treveon paddled 27 miles downstream in his boat. The speed of the water current was 3 mph.
B)Brian paddled 15 miles across the lake in his boat. He was traveling on still wa
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Question 719967: A)Treveon paddled 27 miles downstream in his boat. The speed of the water current was 3 mph.
B)Brian paddled 15 miles across the lake in his boat. He was traveling on still water.
C)The total trip took 10 hours.
- Create an equation for each and then solve them
Attempt -
A) 1A: Distance rowed = time to arrive(row speed still water + Current)
step
2A: 27=x(Y+3) assuming x is time and y is row speed (still)
3A: 27=x(8.43+3)
4A: 27=11.43X
5A: X=2.36 same as time to arrive (subtract this from the total of 6.43 hours for how long it took to get back)
B)
1B: Distance Rowed - time(speed)
2B: 15=xy assuming x is time and Y is row speed
3B: 15=3.57/2(y)
4B:15=1.78(Y)
5B: divide both sides by 1.78
5B: y = 8.43 same as speed equals 8.43
C)--Lost--using part over whole method determining the percentage of whole each traveled (wrong method)
I can determine that Treveon of course took 64.3% of the time equaling 6.43 hours and that bryan took 35.7% equaling 3.57 hours. Bryan's would be equally divided since he didn't have to row up stream...
D) How long did it take each to get back?
Brian is 1.79 hours each way
Treveon is 6.43-2.36 there = 4.07 back
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