SOLUTION: How do you state the equation of the midline for y=sin theta/2 + 1/2

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Question 719863: How do you state the equation of the midline for y=sin theta/2 + 1/2
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Please put arguments to functions in parentheses. What you posted meant:
y=sin%28theta%2F2%29+%2B+1%2F2
but you might have intended:
y=sin%28+theta%2F2+%2B+1%2F2%29
Without the parentheses we can't tell the difference.

The midline of a sin function is a horizontal line. The equation of all horizontal lines have the form:
y = number

The midline of the first equation above is y = 1/2
The midline of the second equation above is y = 0