SOLUTION: A consultant traveled 4 hours to attend a meeting. The return trip took only 3 hours because the speed was 7 miles per hour faster. What was the consultant's speed each way?
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Question 71972: A consultant traveled 4 hours to attend a meeting. The return trip took only 3 hours because the speed was 7 miles per hour faster. What was the consultant's speed each way? Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Yuo can use the distance formula: d = rt where: d = distance, r = rate (speed), and t = time of trip. In this problem, the distance out is equal to the distance back, so
For the outbound trip, t = 4 hrs, and speed = so:
For the return trip, t = 3 hrs, and speed = so: but , so: Simplify and solve for Subtract from both sides. mph This is the outbound speed. mph This is the return speed.
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