SOLUTION: Using three consecutive odd integers, such that if three times the second is subtracted from the third, the difference equals negative forty-eight. Find the first integer.

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Question 719701: Using three consecutive odd integers, such that
if three times the second is subtracted from the third,
the difference equals negative forty-eight. Find the
first integer.

Found 2 solutions by CubeyThePenguin, josgarithmetic:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)


(x+2) - 3x = -48
-2x + 2 = -48
-2x = -50
x = 25

The integers are 23, 25, and 27.

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
system%28n%2C+n%2B2%2C+n%2B4%29
Note that the problem description should be done differently. A difference between two numbers is a POSITIVE value or quantity. Not a "negative" one.

%28n%2B4%29-3%28n%2B2%29=-48
-
n%2B4-3n-6=-48
-2n-2=-48
n%2B1=24
n=23

The integers are 23, 25, 27.