Question 719545: please help me solve this equation: "four times the second of three consecutive integers equals the sum of the first and third integers. find the integers."
Answer by icecream12(3)   (Show Source):
You can put this solution on YOUR website! Let "n" represent the first number of the three consecutive numbers.
4(n+1) = n+(n+2)
4n +4 = n+(n+2) Use the Distributive property
3n + 4 = n + 2 Subtract common terms
2n + 4 = 2 Subtract common terms
2n = -2 Subtract 4 from both sides
-------- Divide by 2
2
n = -1 Solution
Therefore, the three consecutive integers would be n, n+1, and n+2 (-1, 0, 1)
Just remember that three consecutive numbers or integers can be defined as a variable added by 1,2,3... whatever. Hope this helped!
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