SOLUTION: how do you do lgarithmic properties to solve an equation this is what i have log2x+logx=11 log((2x)x)=11 11 (2x)x=10 2 2x -110=0

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: how do you do lgarithmic properties to solve an equation this is what i have log2x+logx=11 log((2x)x)=11 11 (2x)x=10 2 2x -110=0      Log On


   

Question 719220: how do you do lgarithmic properties to solve an equation
this is what i have
log2x+logx=11
log((2x)x)=11
11
(2x)x=10
2
2x -110=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
log2x+logx=11
log(2x*x)=log(11)
2x^2=11
x^2=11/2
x=√(11/2)≈2.35