SOLUTION: find the center of the ellipse below. (x+5)^2/25+(y-1)^2/36=1

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Question 719109: find the center of the ellipse below. (x+5)^2/25+(y-1)^2/36=1
Found 2 solutions by jsmallt9, lynnlo:
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B5%29%5E2%2F25%2B%28y-1%29%5E2%2F36=1
The standard form for the equation of an ellipse is:
%28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1 for horizontal ellipses
and
%28x-h%29%5E2%2Fb%5E2+%2B+%28y-k%29%5E2%2Fa%5E2+=+1 for vertical ellipses
When the equation of an ellipse is in standard form, the coordinates of the center are (h, k). So we can find the center of your ellipse by transforming it into standard form and then reading the h and k values.

To transform your equation into standard form, all we have to do is rewrite the first numerator as a subtraction:
%28x-%28-5%29%29%5E2%2F25%2B%28y-1%29%5E2%2F36=1
and rewrite the denominators as perfect squares:
%28x-%28-5%29%29%5E2%2F5%5E2%2B%28y-1%29%5E2%2F6%5E2=1
From this we can see that the center is (-5, 1).

Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
CENTER IS(-5,1)