SOLUTION: Please help! How do I factor, if possible, the following? (a) y^2 + 16y + 64 (b) by + 7b - 6y - 42 How do I solve the following for the roots of each quadratic equati

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help! How do I factor, if possible, the following? (a) y^2 + 16y + 64 (b) by + 7b - 6y - 42 How do I solve the following for the roots of each quadratic equati      Log On


   



Question 71901This question is from textbook Beginning Algebra
: Please help!
How do I factor, if possible, the following?
(a) y^2 + 16y + 64
(b) by + 7b - 6y - 42
How do I solve the following for the roots of each quadratic equation?
(c) x^2 - x - 20 = 0
(d) 9x^2 = 81
I have been working on these problems for the past few hours, but can't seem to solve using the right formula. Maybe there is something I am doing wrong.
This question is from textbook Beginning Algebra

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Factor:
(a) y%5E2+%2B+16y+%2B+64 Notice that the first and last terms are perfect squares. This suggests the possibility that the expression itself may be a perfect square. Since sqrt%2864%29+=+8, you can try:
y%5E2%2B16y%2B64+=+%28y%2B8%29%28y%2B8%29
Check using FOIL:
%28y%2B8%29%28y%2B8%29+=+y%5E2%2B8y%2B8y%2B64 = y%5E2%2B16y%2B64
The factors are: y%2B8 and y%2B8
(b) by%2B7b-6y-42 Here, you use use "factor by grouping". Group the terms as folows:
%28by%2B7b%29+-+%286y%2B42%29 Notice the change of sign on the last term when the parentheses were added. Now, from each group, factor the common factors.
b%28y%2B7%29+-+6%28y%2B7%29 Now you can factor the common factor of (y+7)
%28y%2B7%29%28b-6%29 These are the factors.
Solve:
(c) x%5E2-x-20+=+0 This will factor. Notice that the last term has factors of 4 and 5. Also notice that 4-5 = -1 and this is the coefficient of the middle term. So we try:
x%5E2-x-20+=+%28x%2B4%29%28x-5%29
%28x%2B4%29%28x-5%29+=+0 Apply the zero product principle:
x%2B4+=+0 and/or x-5+=+0
If x%2B4+=+0 then x+=+-4
If x-5+=+0 then x+=+5
The roots are:
x+=+-4
x+=+5
(d)
9x%5E2+=+81 Notice that both sides are perfect squares.
%283x%29%5E2+=+%289%29%5E2 Take the square root of both sides.
3x+=+sqrt%289%5E2%29
3x+=+-9 or 3x+=+9 Divide both sides by 3.
x+=+-3 or x+=+3