SOLUTION: find the center and radius of the circle whose equation is {{{x^2+(y+2)^2=25}}}

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Question 718829: find the center and radius of the circle whose equation is x%5E2%2B%28y%2B2%29%5E2=25
Found 2 solutions by jim_thompson5910, solver91311:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2B%28y%2B2%29%5E2=25

%28x-0%29%5E2%2B%28y-%28-2%29%29%5E2=25

%28x-0%29%5E2%2B%28y-%28-2%29%29%5E2=5%5E2

Compare the last equation to %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2

We see that h = 0, k = -2 and r = 5

So the center is (0, -2) and the radius is 5 units.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




is the equation of a circle centered at with radius .

To answer your question, it will be convenient to re-write your equation thusly:



The answers you need are now available by inspection.

John

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