SOLUTION: Please help me find the inverse to this equation: y=6+log(base10)of x. I've gotten to x-6=log(base10) of y, but I'm not sure how to isolate the log(base10) from y.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Please help me find the inverse to this equation: y=6+log(base10)of x. I've gotten to x-6=log(base10) of y, but I'm not sure how to isolate the log(base10) from y.       Log On


   

Question 718696: Please help me find the inverse to this equation: y=6+log(base10)of x. I've gotten to x-6=log(base10) of y, but I'm not sure how to isolate the log(base10) from y.
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
You're good so far with:
x-6+=+log%2810%2C+%28y%29%29
The next step is to rewrite the equation in exponential form. (That is how you get rid of the log.) In general log%28a%2C+%28p%29%29+=+q is equivalent to p+=+a%5Eq. Using this pattern on your equation we get:
10%5E%28%28x-6%29%29+=+y
This is the inverse.