SOLUTION: A bacteria culture started with a count of 720 at 8:00 am, and after t hours is expected to grow to f(t)=720(3/2)^t. Estimate the number of bacteria in the culture at 11:00 am the

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Question 71851: A bacteria culture started with a count of 720 at 8:00 am, and after t hours is expected to grow to f(t)=720(3/2)^t. Estimate the number of bacteria in the culture at 11:00 am the same day.
Answer by ankor@dixie-net.com(22740) (Show Source):
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A bacteria culture started with a count of 720 at 8:00 am, and after t hours is
expected to grow to f(t)=720(3/2)^t. Estimate the number of bacteria in the
culture at 11:00 am the same day.
:
That would be after 3 hrs, can be done directly on a calc, however if they want you to use logs:
:
y = f(t)
y = 720(3/2)^3
ln(y) = ln(720) + ln(3/2)^3
ln(y) = 6.57925 + 3*ln(.405465); log equiv of exponents
ln(y) = 6.57925 + 1.2164
ln(y) = 7.795645
y = e^x of 7.795645 = 2429.99 ~ 2430
:
Check on a good calc: enter: 720*(1.5^3)