SOLUTION: How do you write 5log[base2]x+(1/2)log[base2]y as a single logarithm

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Question 718443: How do you write 5log[base2]x+(1/2)log[base2]y as a single logarithm
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
5log%282%2C+%28x%29%29%2B%281%2F2%29log%282%2C+%28y%29%29
We have two logs which we want to write as one log. There are two ways to combine two logarithmic terms into one:
  • If they are like terms we can add or subtract them (depending on whether there's a "+" or "-" between them. Like logarithmic terms have the same bases and the same argument.
  • Use one of the following properties of logarithms:
    • log%28a%2C+%28p%29%29+%2B+log%28a%2C+%28q%29%29+=+log%28a%2C+%28p%2Aq%29%29
    • log%28a%2C+%28p%29%29+-+log%28a%2C+%28q%29%29+=+log%28a%2C+%28p%2Fq%29%29
    These properties require logs with the same base and coefficients of 1.
Our logs have the same bases, 2. But the arguments, x and y, are different. So we cannot add them together. Also our logs have coefficients, 5 and 1/2, which are not 1's. So we cannot use the properties... yet. Fortunately there is another property of logs, log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29, which will help. The right side shows a log with a coefficient which is not a 1. The left side shows us how to rewrite the right side with a coefficient of 1: Just move the coefficient into the argument as its exponent!

So we start by using the property which lets us move the coefficients:
log%282%2C+%28x%5E5%29%29%2Blog%282%2C+%28y%5E%281%2F2%29%29%29
Since an exponent of 1/2 means square root, I'm going to rewrite it as a square root:
log%282%2C+%28x%5E5%29%29%2Blog%282%2C+%28sqrt%28y%29%29%29

Now we will use log%28a%2C+%28p%29%29+%2B+log%28a%2C+%28q%29%29+=+log%28a%2C+%28p%2Aq%29%29 (because its logs, like ours, have a "+" between them) to combine the logs:
log%282%2C+%28x%5E5%2Asqrt%28y%29%29%29