SOLUTION: Please can someone give me the Steps for this type of question please.I understand u should take out whats common etc.. but i need to understand if i should factor 2x and the 4 .so

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please can someone give me the Steps for this type of question please.I understand u should take out whats common etc.. but i need to understand if i should factor 2x and the 4 .so      Log On


   

Question 718032: Please can someone give me the Steps for this type of question please.I understand u should take out whats common etc.. but i need to understand if i should factor 2x and the 4 .someone please just give me the steps .Thanks
2x(x+6)^4-x^2(4)(x+6)^3 divided by (x+6)^8
Found 2 solutions by josgarithmetic, gingertea:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
2x%28x%2B6%29%5E4-x%5E2%284%29%28x%2B6%29%5E3 divided by %28x%2B6%29%5E8, factor the dividend. This is just like simplifying a fraction, no different.

The dividend is %28x%2B6%29%5E3%282x%28x%2B6%29-4x%5E2%29
=2x%28x%2B6%29%5E3%28x%2B6-2x%29
=2x%28x%2B6%29%5E3%28-x%2B6%29

Now you are looking for the dividend divided by the divisor:
%282x%28x%2B6%29%5E3%28-x%2B6%29%29%2F%28%28x%2B6%29%5E8%29
=highlight%282x%28-x%2B6%29%2F%28%28x%2B6%29%5E5%29%29, before doing other multiplications.

Answer by gingertea(7) About Me  (Show Source):
You can put this solution on YOUR website!
%282x%28x%2B6%29%5E4+-+x%5E2%284%29%28x%2B6%29%5E3%29%2F%28x%2B6%29%5E8
By factorisation ,
=%28%282x%28x%2B6%29%5E3%29%2A%28x%2B6%29-2x%29%2F%28%28x%2B6%29%5E8%29
if you time the 1st bracket you will get the equation of your question,
then cancle out the common factor,which is (x+6)^3
=%28%282x%28x%2B6%29%5E3%29%2A%28x%2B6%29-2x%29%2F%28%28x%2B6%29%5E3%2A%28x%2B6%29%5E5%29
you will get
%282x%28%28x%2B6%29-2x%29%29%2F%28%28x%2B6%29%5E5%29