SOLUTION: a collection of nickels,dimes and quarters consists of 9 coins with a total value of 1.20 if the number of dimes is equal to the number of nickels,find the number of each type of c
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Question 717986: a collection of nickels,dimes and quarters consists of 9 coins with a total value of 1.20 if the number of dimes is equal to the number of nickels,find the number of each type of coin. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! a collection of nickels,dimes and quarters consists of 9 coins with a total value of 1.20
if the number of dimes is equal to the number of nickels,
find the number of each type of coin.
:
Let c = no. nickels and no. of dimes
Let q = no. quarters
:
Two equations
2c + q = 9
q = (9-2c)
and
.05c + .10c + .25q = 1.20
.15c + .25q = 1.20
replace q with (9-2c)
.15c + .25(9-2c) = 1.20
.15c + 2.25 - .50c = 1.20
.15c - .50c = 1.20 - 2.25
-.35c = -1.05
c = -1.05/-.35c
c = + 3 nickels and 3 dimes
;
You can find the number of quarters; check the total amt with these values
